Only skilled people can open this file.......once you succeed to open this file, you will find names of the people who have managed open this....... now it is your turn!
A man wanted to get into his work building, but he had forgotten his access code.
However, he did remember five clues. These are the clues:
The fifth number plus the third number equals fourteen.
The fourth number is one more than the second number.
The first number is one less than twice the second number.
The second number plus the third number equals ten.
The sum of all five numbers is 30.
What were the five numbers and in what order?
The correct answer unlocks the attached file!
If you open the file, write your name on the list inside, and send this
Email to your friends to let them solve this riddle.
There are many valid combinations, assuming that the same number (digit) can be used twice or more.
KevinJ said
07:14 PM Aug 23, 2019
As far as I am aware, there is only 1 combination.
Whenarewethere said
09:22 PM Aug 23, 2019
If you start with the second line first you have 16. The first line is a distraction.
KevinJ said
09:27 PM Aug 23, 2019
I can assure you that you will need all 5 clues
dorian said
04:21 AM Aug 24, 2019
KevinJ wrote:
As far as I am aware, there is only 1 combination.
Here are 4 possible combinations (the third combination has dissimilar digits):
2 5 5 9 9 3 5 5 8 9 * * * * * 4 4 6 8 8
There are 11 solutions, 3 with dissimilar digits.
-- Edited by dorian on Saturday 24th of August 2019 08:15:45 AM
KevinJ said
09:52 AM Aug 24, 2019
Did you try to open the spreadsheet at the bottom of my original post? It would not open for me using any of the numbers below.
My feedback:
Rules
1. The fifth number plus the third number equals fourteen. 2. The fourth number is one more than the second number. 3. The first number is one less than twice the second number. 4. The second number plus the third number equals ten. 5. The sum of all five numbers is 30.
a b c d e 2 5 5 9 9 - Fails on rule 2 and fails on rule 3. 3 5 5 8 9 - Fails on rule 2 and fails on rule 3. * * * * * 4 4 6 8 8 - Fails on rule 2 and fails on rule 3.
dorian said
10:40 AM Aug 24, 2019
KevinJ wrote:
Did you try to open the spreadsheet at the bottom of my original post? It would not open for me using any of the numbers below.
My feedback:
Rules
1. The fifth number plus the third number equals fourteen. 2. The fourth number is one more than the second number. 3. The first number is one less than twice the second number. 4. The second number plus the third number equals ten. 5. The sum of all five numbers is 30.
a b c d e 2 5 5 9 9 - Fails on rule 2 and fails on rule 3. 3 5 5 8 9 - Fails on rule 2 and fails on rule 3. * * * * * 4 4 6 8 8 - Fails on rule 2 and fails on rule 3.
Doh, I didn't see the "one more" and "one less" conditions. Back to the drawing board ...
Edit:
OK, I got it this time. There is only one solution, as you say.
Let the 5-digit code be abcde.
Analysing each of the 5 statements in turn we get ...
1/ e + c = 14
2/ d = b + 1
3/ a = 2b - 1
4/ b + c = 10
5/ a + b + c + d + e = 30
from 1:
e = 14 - c
from 4:
b = 10 - c
from 2:
d = b + 1 = 11 - c
from 3:
a = 2b - 1 = 2 x (10 - c) - 1 = 19 - 2c
from 5:
a + b + c + d + e = (19 - 2c) + (10 - c) + c + (11 - c) + (14 - c) = 54 - 4c
54 - 4c = 30
The rest is straight substitution.
-- Edited by dorian on Saturday 24th of August 2019 10:57:11 AM
KevinJ said
03:33 PM Aug 24, 2019
Good one. Now all you have to do is open the spreadsheet, add your name and then pass it on.
Your logic is right on track as this is an algebraic substitution puzzle.
Whenarewethere said
07:17 PM Aug 24, 2019
The first line is a distraction, put the 14 aside. You have 16 to play with.
Two is 1 less than Four, so 4 & 5, to have enough from 16.
One has to be 1 less than twice Two, so 7 & 4.
The three add up to 16.
Two & Three add up to 10, so 4 & 6.
Which leaves 8 to add up to 30.
74658
KevinJ said
08:43 AM Aug 25, 2019
It just shows there is more than one way to solve a problem. I used a different way to both the two solutions here.
Whenarewethere said
09:13 AM Aug 25, 2019
Having an equation is better, but I did manage to juggle the numbers in my head..... just!
Starting with line two & also thinking of two is 1 less than four was easier the four 1 more than two, for me anyway.
dabbler said
05:01 PM Aug 25, 2019
Couldn't manage it in my head. Has to resort to the back of an envelope. Like most of these algebraic problems presented as puzzles, a lot of confusion depends of wording.
dorian said
08:05 AM Aug 26, 2019
dabbler wrote:
Like most of these algebraic problems presented as puzzles, a lot of confusion depends of wording.
I'm noticing that I miss entire words when I read and also when I write. This is happening more often. I wonder if it is a sign that something is wrong upstairs. In this particular case I mistook "one more" and "one less" for "more" and "less", which then left me with this:
1/ e + c = 14
2/ d > b
3/ a < 2b
4/ b + c = 10
5/ a + b + c + d + e = 30
That's why I found 11 solutions.
KevinJ said
08:44 AM Aug 26, 2019
"It deosn't mttaer in waht oredr the ltteers in a wrod are, the olny iprmoetnt tihng is taht the frist and lsat ltteer be at the rghit pclae. The rset can be a toatl mses and you can sitll raed it wouthit porbelm. Tihs is bcuseae the huamn mnid deos not raed ervey lteter by istlef, but the wrod as a wlohe."
Mattt said
01:02 PM Aug 27, 2019
Exactly the same thing has been happening to me. And worrying the hell outta me. Not like I'm uneducated or stupid or anything like it. Yet did actually use the backspace key perhaps half a dozen time while typing this post. And I type for a living...
Bugger. Was answering Dorian's post.
-- Edited by Mattt on Tuesday 27th of August 2019 01:03:42 PM
Only skilled people can open this file.......once you succeed to open this file, you will find names of the people who have managed open this....... now it is your turn!
A man wanted to get into his work building, but he had forgotten his access code.
However, he did remember five clues. These are the clues:
The fifth number plus the third number equals fourteen.
The fourth number is one more than the second number.
The first number is one less than twice the second number.
The second number plus the third number equals ten.
The sum of all five numbers is 30.
What were the five numbers and in what order?
The correct answer unlocks the attached file!
If you open the file, write your name on the list inside, and send this
Email to your friends to let them solve this riddle.
There are many valid combinations, assuming that the same number (digit) can be used twice or more.
As far as I am aware, there is only 1 combination.
If you start with the second line first you have 16. The first line is a distraction.
I can assure you that you will need all 5 clues
Here are 4 possible combinations (the third combination has dissimilar digits):
2 5 5 9 9
3 5 5 8 9
* * * * *
4 4 6 8 8
There are 11 solutions, 3 with dissimilar digits.
-- Edited by dorian on Saturday 24th of August 2019 08:15:45 AM
Did you try to open the spreadsheet at the bottom of my original post? It would not open for me using any of the numbers below.
My feedback:
Rules
1. The fifth number plus the third number equals fourteen.
2. The fourth number is one more than the second number.
3. The first number is one less than twice the second number.
4. The second number plus the third number equals ten.
5. The sum of all five numbers is 30.
a b c d e
2 5 5 9 9 - Fails on rule 2 and fails on rule 3.
3 5 5 8 9 - Fails on rule 2 and fails on rule 3.
* * * * *
4 4 6 8 8 - Fails on rule 2 and fails on rule 3.
Doh, I didn't see the "one more" and "one less" conditions. Back to the drawing board ...
Edit:
OK, I got it this time. There is only one solution, as you say.
Let the 5-digit code be abcde.
Analysing each of the 5 statements in turn we get ...
1/ e + c = 14
2/ d = b + 1
3/ a = 2b - 1
4/ b + c = 10
5/ a + b + c + d + e = 30
from 1:
e = 14 - c
from 4:
b = 10 - c
from 2:
d = b + 1 = 11 - c
from 3:
a = 2b - 1 = 2 x (10 - c) - 1 = 19 - 2c
from 5:
a + b + c + d + e = (19 - 2c) + (10 - c) + c + (11 - c) + (14 - c) = 54 - 4c
54 - 4c = 30
The rest is straight substitution.
-- Edited by dorian on Saturday 24th of August 2019 10:57:11 AM
Good one. Now all you have to do is open the spreadsheet, add your name and then pass it on.
Your logic is right on track as this is an algebraic substitution puzzle.
The first line is a distraction, put the 14 aside. You have 16 to play with.
Two is 1 less than Four, so 4 & 5, to have enough from 16.
One has to be 1 less than twice Two, so 7 & 4.
The three add up to 16.
Two & Three add up to 10, so 4 & 6.
Which leaves 8 to add up to 30.
74658
It just shows there is more than one way to solve a problem. I used a different way to both the two solutions here.
Having an equation is better, but I did manage to juggle the numbers in my head..... just!
Starting with line two & also thinking of two is 1 less than four was easier the four 1 more than two, for me anyway.
I'm noticing that I miss entire words when I read and also when I write. This is happening more often. I wonder if it is a sign that something is wrong upstairs. In this particular case I mistook "one more" and "one less" for "more" and "less", which then left me with this:
1/ e + c = 14
2/ d > b
3/ a < 2b
4/ b + c = 10
5/ a + b + c + d + e = 30
That's why I found 11 solutions.
"It deosn't mttaer in waht oredr the ltteers in a wrod are, the olny iprmoetnt tihng is taht the frist and lsat ltteer be at the rghit pclae. The rset can be a toatl mses and you can sitll raed it wouthit porbelm. Tihs is bcuseae the huamn mnid deos not raed ervey lteter by istlef, but the wrod as a wlohe."
Exactly the same thing has been happening to me. And worrying the hell outta me. Not like I'm uneducated or stupid or anything like it. Yet did actually use the backspace key perhaps half a dozen time while typing this post. And I type for a living...
Bugger. Was answering Dorian's post.
-- Edited by Mattt on Tuesday 27th of August 2019 01:03:42 PM